During the construction of an office building a hammer is ac
During the construction of an office building, a hammer is accidentally dropped from a height of 16ft. The distance the hammer falls in t sec is s=16t^2. What is the hammer\'s velocity when it strikes the ground? What is its acceleration?
Solution
16 = 16t2
t^2 = 1
t = 1 -> when the hammers strike ground
v = ds/dt = 16*2t = 32t
t = 1 -> v = 32*1 = 32 ft/s
a = dv/dt = 32*1 = 32 ft/s2
