What is the area in2 of a right triangle that has two 10 inc

What is the area (in^2) of a right triangle that has two 10 inch sides and a longer hypotenuse a. 50.0 b. 53.60 c. 40.0 d. 100.0

two sides of right triangle are 10 inches and 10 inches

==> base and height of triangle are 10 and 10

==> Area A = (1/2)(10)(10) (since area of triangle with base b and height h are (1/2)(b)(h) )

==> A = 100/2

==> A = 50 in²