As shown in Figure 1 a layer of water covers a slab of mate

As shown in (Figure 1) , a layer of water covers a slab of material X in a beaker. A ray of light traveling upward follows the path indicated. Assume that 1 = 48 and 2 = 67

Using the information on the figure, find the index of refraction of material X.

Using the information on the figure, find the angle the light makes with the normal in the air .

Solution

n_x sin theta_x = n_w sin theta_w

n_x = (1.33 * sin 48) / (sin 23)

= 2.53

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n_asin theta_a = n_w sin theta_w

theta_a = sin^-1 [n_w sin theta_w / n_a]

= sin^-1 [1.33 * sin 48 / 1]

= 82 deg