solve for for y when the absolute value of y3 13sqrt3 Solut

solve for for y when the absolute value of y^3 = 1/3sqrt3 .

y^3 = 1/3sqrt3

RHS 1/3sqrt3 = 1/(3*3^1/2) = 1/(3^(1+1/2) )

= 1/(3^3/2)

y^3 = 3^(-3/2)

Taking cube root on both sides:

(y^3)^1/3 = {3^(-3/2)}^1/3

y = 3^(-1/2)

= 1/3^1/2

y = + - 1/sqrt3

y = + - sqrt 3 / 3