How does the user determine where zero voltage for the verti

How does the user determine where zero voltage for the vertical signal is on the oscilloscope display? What is the effect of the AC-DC-GND switches on the voltage signal in the circuit under test? What is the effect on the waveform shown on the display? What is the effect on the waveform display of turning the volts/div knob clockwise? What is the effect on the waveform display of turning the sec/div knob clockwise? What do the vertical position, horizontal position, and trigger position knobs do? What is the ratio of the amplitude measured with the scope to that measured with the multi meter from Step 5? What is the reciprocal of the frequency, 1/f from Step 5 of the procedure?

Solution

1.at the position it meet the the crosspoint of horizontal axis it seems zero voltage.

2.it certainly put the incoming signal grounded.it appeared as straight line inlined to horizental axis.

3.volts/div knobs increases the amplitude of the signal picks,depends how many division is chosen

4.it acts on the time scale ,so the pan of the wave form may be wider or shrinker through the horizontal axis.

5.vertical position control the amplitude,horizontal position controls the time period of osc and trigger control some external addition of voltages.

6.here it is 1:1 as 1 div/1volt(vertical) and 1:1 as 1 div/1sec(horizontal)

7.the reciprocal of frequency is T as time period.

7.