ssume A 78 g basketball is launched at an angle of 419 and a

ssume: A 78 g basketball is launched at an
angle of 41.9? and a distance of 18.5 m from
the basketball goal. The ball is released at the
same height (ten feet) as the basketball goal

Solution

Plot the points (0,0) and (18.5,0) on the x-axis
(0,0) is the point of release; (18.5,0) is the basket
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Equation: s(t) = -9.8t^2 + vt
s is the height at time t
v is the release velocity
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Your Problem:
-9.8t^2 + vt = 0
t(-9.8t + v) = 0
t = 0 or t = v/9.8