A XwmXwm female was mated to a XwmY male Out of 1000 total F
A Xw+m+Xwm female was mated to a XwmY male. Out of 1000 total F1 progeny there were 230 flies that were otherwise wild type with white eyes and 240 flies that were otherwise wild type with miniature wings. What is the distance between the genes for eye color and wing length?
A. 47 map units
B. 24 map units
C. 53 map units
D. 23 map units
Solution
The relative distance between the genes (gene distance) can be measured from the recombination frequency. The percentage of recombination or crossing over is equivalent to map unit or centimorgan (cM). 1 map unit or 1 cM is equal to 1 % recombination. The distance between the genes or map distance is given by the equation:
(No: of recombinant offspring/Total no: of offspring) X 100
Here, the total no : of offspring = 1000
No: of recombinant progeny = 1000- (parental /wild types)
= 1000- (230+240) =530.
Recombination frequency = (530/1000) x 100 = 53
The answer is C.53 map units.
