Let x be a random variable that represents red blood cell co
Solution
Formulating the null and alternative hypotheses,
Ho: u >= 4.6
Ha: u < 4.6
As we can see, this is a left tailed test.
Thus, getting the critical t,
df = n - 1 = 5
tcrit = - 3.364929999
Getting the test statistic, as
X = sample mean = 4.4
uo = hypothesized mean = 4.6
n = sample size = 6
s = standard deviation = 0.28
Thus, t = (X - uo) * sqrt(n) / s = -1.749635531
Also, the p value is
p = 0.070294186
As |t| < 3.365, and P > 0.01, we FAIL TO REJECT THE NULL HYPOTHESIS.
Thus, there is no significant evidence that the mean RBC level for this patient is less than 4.6. [conclusion]
