How i can solve it with the full solution please Force F ac

Force F acts on the frame such that its component acting along m directed from B towards A, and the component acting along membr from B towards C. Using cosine and sine law determine the mag . Set = 60°. omponent acting along member AB is 650 N along member BC is 500 N, directed determine the magnitude of F and its direction . Using cosine and sine law determine the magnitu 45 db Write your final answers here (3 significant figures) R= degrees

Solution

This one was a bit tough, and I\'m not 100% sure about theta (but I\'m pretty confident, I solved it with two methods and it gave me the same value), but here you go. The 2nd method is probably easier to undertand.

Method 1:
Divide in two equations, for xx and yy, where xx points to the right, parallel to the ground and yy points vertically and upwards.

xx: Fx=-F1cos(60)+F2cos(45)
yy: Fy=-F1sen60-F2sen45

Where Fx and Fy are the F components along the axis and F1=FAB=650, F2=FBC=500

Fx=28.55
Fy=-916.45

And also
Fx=Fcos(Theta+60)
Fy=Fsen(Theta+60)
Fy/Fx=tan(theta+60)-->theta=tan-1(Fy/F... - 60->theta=-148.21
I think this theta is from the xx axis, so if you do -180-theta ->theta\'=31.8, which is the theta in the figure. I don\'t fully understand why it gives that kind of angle, but the 2nd method gives the same, take a look, maybe it is easier.

Method 2:
I want to apply trigonometric relations, but I needed a 90