Ch 0 Ta Test Help CS ted to test whether the population mean

Ch.. 0 Ta Test Help CS ted to test whether the population mean is smaller than 15. The sample showed an average of 14.3 and a standard deviation of 2.7. You want to test this using the crtical value approach ESTION 22 A sample of i observations has been selec Second, compute the difference between the test First, compute the critical value and the test statistics associated with this test. Second, compute the c hypothesis at93% level of eatistic and the critical value (test statistic-critical value). What is this OTE: WRITE YOUR ANSWER WITH 4 DECIMAL DIGITS DO NOT ROUND UP OR DOWN MAKE SURE YOU INDICATE THE SIGN OF THIS DIFFERENCE CORRECTLY UESTION 23 Ahmad, Inc. has been manufacturing small automobiles that heve averaged S0 miles per gallon of gasoline in highway driving. The company has developed a more efficient engine for its small cars and adverties that is w small c verage more than 50 miles per gall nh hway dning To test this hypothesis at 9 % level o confidence, an independent testing service road tested 4 of the automobiles. The sample showed an average of S1 miles per galion Assume that the populati on standard deviation is 4 miles per gallon. Compute the p-vailues associated with this test NOTE: WRITE YOUR ANSWER WITH 4 DECIMAL DIGITS.DO NOT ROUND UP OR DOWN. UESTION 24 Ahmad, Inc. has been manufacturing small automobiles that have averaged 50 miles per gallon of gasoline in highway driving. The company has developed a more efficient engine for its small cars and now advertises that its new small cars average more than 50 mles per gallon in highway driving. An independent testing service road-tested 64 of the automobiles. The sample showed an average of 51 miles per gallon with a standard deviation of 4 miles per gallon. You want to test whether or not the manufacturer\'s advertising NOTE WRITE YOUR ANSWER WITH 4 DECIMAL DIGITS. DO NOT ROUND UP OR DOWN to save alla

Solution

Q22.
Set Up Hypothesis
Null, H0: U>15
Alternate, H1: U<15
Test Statistic
Population Mean(U)=15
Sample X(Mean)=14.3
Standard Deviation(S.D)=2.7
Number (n)=81
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =14.3-15/(2.7/Sqrt(80))
to =-2.333
| to | =2.333
Critical Value
The Value of |t | with n-1 = 80 d.f is 1.491
Diffrence b/w the test statistic - critical value = 2.333-1.491 = 0.842
We got |to| =2.333 & | t | =1.491
Make Decision
Hence Value of | to | > | t | and Here we Reject Ho
P-Value :Left Tail -Ha : ( P < -2.3333 ) = 0.01107
Hence Value of P0.07 > 0.01107,Here we Reject Ho