With individual lines at the checkouts a store manager finds
With individual lines at the checkouts, a store manager finds that the standard deviation for the waiting times on monday mornings is 5.2 minutes. After switching to a single waiting line, he finds that for a random sample of 29 customers the waiting times have a standard deviation of 4.3 minutes. Assume that line wiaitng times on monday are normally distributed. Use .05 significance level to test whether the standard deviation of the waiting times using a single line differs from 5.2 minutes. (include hypotheses, test, assumptions, & summary)
Solution
Formulating the null and alternative hypotheses,
Ho: sigma = 5.2
Ha: sigma =/ 5.2 [ANSWER, HYPOTHESES]
As the waiting times are normally distributed, we can do the chi^2 test.
As we can see, this is a two tailed test.
Thus, getting the critical chi^2, as alpha = 0.05 ,
alpha/2 = 0.025
df = N - 1 = 28
chi^2 (crit) = 15.30786055 and 44.46079184
Getting the test statistic, as
s = sample standard deviation = 4.3
sigmao = hypothesized standard deviation = 5.2
n = sample size = 29
Thus, chi^2 = (N - 1)(s/sigmao)^2 = 19.1464497
As chi^2 is between the two critical values, we FAIL TO REJECT THE NULL HYPOTHESIS.
Thus, there is no significant evidence that the standard deviation of the waiting times using a single line differs from 5.2 minutes. [CONCLUSION]
