find the six trigonometric ratios of angle A rounded to thre

find the six trigonometric ratios of angle A rounded to three significant digits?

step #1
find the pythagorean theorem a^2+b^2=c^2

a=335m, c=685m

Solution

a^2+b^2=c^2

means it is a right angle triangle at \'C\'

we will find \'b\' ( AC) length using above theorem

(335)^2 + b^2 = (685)^2

112225 +b^2 = 469225

b^2 = 469225 - 112225

b^2 = 357000

b = 597.495 m

now we know three side lengths

let us the angle is \'x\'

then sin(x) = a/c

= 335/685

= 0.48905

cos(x) = b/c

=597.495 / 685

= 0.8722

tan(x) = a/b = 335/597.495

= 0.561

cot(x) =1/tan(x) = 1/0.561 = 1.783

cscx = 1/sinx = 1/0.48905 = 2.045

secx = 1/cosx =1/0.872=1.147

find the six trigonometric ratios of angle A rounded to three significant digits? step #1 find the pythagorean theorem a^2+b^2=c^2 a=335m, c=685mSolutiona^2+b^2

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