find the six trigonometric ratios of angle A rounded to thre
find the six trigonometric ratios of angle A rounded to three significant digits?
step #1
find the pythagorean theorem a^2+b^2=c^2
a=335m, c=685m
Solution
a^2+b^2=c^2
means it is a right angle triangle at \'C\'
we will find \'b\' ( AC) length using above theorem
(335)^2 + b^2 = (685)^2
112225 +b^2 = 469225
b^2 = 469225 - 112225
b^2 = 357000
b = 597.495 m
now we know three side lengths
let us the angle is \'x\'
then sin(x) = a/c
= 335/685
= 0.48905
cos(x) = b/c
=597.495 / 685
= 0.8722
tan(x) = a/b = 335/597.495
= 0.561
cot(x) =1/tan(x) = 1/0.561 = 1.783
cscx = 1/sinx = 1/0.48905 = 2.045
secx = 1/cosx =1/0.872=1.147
