Q1 Suppose that in a senior college class of 500 students it
Solution
a) Number of students that smokes but does not drink soft drinks = number of students that smokes - number of students that smoke & drinks soft drink = 210 - 122 = 88
Therefore, P( smokes but does not drink soft drinks) = 88/500 = 0.176
b) Number of students that eats between meals and drinks soft drinks but does not smoke = Number of students that eats between meals and drinks soft drinks - number of students engaged in all three practices = 83 - 52 = 31
Therefore, P(eats between meals and drinks soft drinks but does not smoke) = 31/500 = 0.062
c) Number of students that either smokes or eats between meals = number of students that smokes + number of students that eat between meals - number of students that smokes and eat between meals = 210 + 216 -97 = 329
Thus, Number of students that neither smokes nor eats between meals = 500 - Number of students that either smokes or eats between meals = 500 - 329 = 171
Therefore, P(neither smokes nor eats between meals) = 171/500 = 0.342
