The point is on the terminal side of an angle in standard po

The point is on the terminal side of an angle in standard position. Determine the exact values of the six trigonometric functions of the angle. (-48, 14) 0 sin cos 0 tan csc 0 sec 0- cot 0

Solution

Point is (-48,14)

tan theta=y/x = 14/-48= -7/24

Here opposite=7 and adjacent=24

Hypotenuse=sqrt(72 +242) =25

Sin theta=opposite/hypotenuse= 7/25

Cos theta=adjacent/hypotenuse= -24/25

Csc theta=1/sin theta = 25/7

Sec theta= 1/cos theta= -25/24

Cot theta=1/tan theta= -24/7

 The point is on the terminal side of an angle in standard position. Determine the exact values of the six trigonometric functions of the angle. (-48, 14) 0 sin

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