following data reps demand for items from the store over 14

following data reps demand for items from the store over 14 dayz. Split the data in to 2 equal parts of 7 days each. Assume F1 = 198.

Make spreadsheet using the first 7 days of demand to see the best exponential smoothing model for values of = 0.2, = 0.3, = 0.4. pick the model with the smallest absolute deviation for 7periods.

Make another spreadsheet using the holdout sample for the second 7 days to compare the best exponential smoothing model found in part a with a 3PMA three-period moving average model. Compare predictions on the basis of the total absolute deviation for the 7 periods.

What principles does this problem show?

Day Demand Day Demand
1 200 8 208
2 209 9 186
3 215 10 193
4 180 11 197
5 190 12 188
6 195 13 191
7 200 14 196

Solution

The next 7 days give less absolute deviation for this model.

This problem shows that forecast are more accurate in the shorter term than longer time horizons.

Day Demand Exponential soomthing at 0.2 Absolute Mean devation Exponential soomthing at 0.3 Absolute Mean devation Exponential soomthing at 0.4 Absolute Mean devation
1 200
2 209 200 9 200 9 200 9
3 215 207.2 7.8 206.3 8.7 205.4 9.6
4 180 213.44 33.44 212.39 32.39 211.16 31.16
5 190 186.688 3.312 189.717 0.283 192.464 2.464
6 195 189.3376 5.6624 189.9151 5.0849 190.9856 4.0144
7 200 193.86752 6.13248 193.47453 6.52547 193.39424 6.60576
10.89114667 10.33056167 10.47402667
following data reps demand for items from the store over 14 dayz. Split the data in to 2 equal parts of 7 days each. Assume F1 = 198. Make spreadsheet using the

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