e42 e05 e002 1e3 Given 30I 5l 5 solve for l Given 1
e^+4.2 = _________ e^+0.5 = _________ e^-0.02 =_________ 1/e^-3 = ________ Given 30I = 5l + 5, solve for l. Given 1/R^T = 1/R^1 + 1/4R^1, solve for Rtau in terms of R1.
Solution
e^4.2 = 66.686
e^0.5 = 1.649
e^-0.02 = 0.980
1/e^-3 = 20.086
30I = 5I + 5
25I = 5
I = 5/25
I = 1/5 ---> answer for I
-=--------------------------------------------
1/Rt = 1/R1 + 1/4R1
1/Rt = 4/4R1 + 1/4R1
1/Rt = 5/4R1
Crossmultiplying :
5Rt = 4R1
Rt = 4R1/5 ---> answer
