Given the equation y 5sin6x pi 4 find the following Ampli

Given the equation y = -5sin(6x + pi) - 4 find the following: Amplitude: Period: Horizontal Shift (phase shift): Towards right or left: Vertical Shift: Upward or Downward: Let\'s assume sin(theta) = 12/13 and theta is in quadrant 1. Find the following. tan(theta) = sec(theta) = If possible, find the exact value. If it is not possible, write undefined sin (tan^-1 (-3/4)) = If possible, find the exact value. If it is not possible, write undefined. sin^-1 (-2) = If possible, find the exact value. If it is not possible, write undefined. sin^-1(cos(pi)) = If possible, find the exact value. If it is not possible, write undefined. cos (sin^-1 (1/2)) = Determine which of the four quadrants angle theta is located in if sin theta > 0 and sec theta > 0. Find tan theta, if cot theta = squareroot 15/3.

Solution

y=-5sin(6x+ pi) - 4

Phase shift

for f(t)=Asin(Bx+C) +D

Phase shift is C/B

Here C is pi and B is 6,therefore phase shift is pi/6

Period = 2pi/B=2pi/6= pi/3

Amplitude is A

Therefore amplitude= -5

And it will shift towards left because of + pi