Solve for and give Vb if the LED forward voltage is 3 and th
Solution
APPLLY KVL IN LOOP
-Vb+200i+3300i=0
in problem given that i =10ma
-Vb=-500i-3
-vb=-[500i+3]
vb=500i+3
=500*10*10^-3+3
5+3
=8
so vb=8v

APPLLY KVL IN LOOP
-Vb+200i+3300i=0
in problem given that i =10ma
-Vb=-500i-3
-vb=-[500i+3]
vb=500i+3
=500*10*10^-3+3
5+3
=8
so vb=8v
