In the circuit shown below W1 10000 lbf W2 20000 lbf D1p

In the circuit shown below, W1 = 10,000 lbf, W2 = 20,000 lbf, D1,p = D2,p = 6 in, and D1,r = D2,r = 3 in. There is no friction, and both cylinders are full of oil. If cylinder #2 is extending at 3 in/s, what is the speed of cylinder #1?

Solution

sol : mv²/r = constant

m₁v₁²/r₁ =m₂v₂²/r₂

we know w = mg   

m= w/g

w₁v₁²/r₁   = w₂v₂²/r₂

10000*v₁²/3 = 20000*9/3

v₁²   = 18

v₁   = 4.243 in/s