A dihybrid com plant was test crossed and five possible data
Solution
Data set 1:
total number of plants = 239 + 69 + 95 + 247 = 650
Frequency of gene E = 239 + 69 = 308/650 = 0.47
Frequency of gene F = 239 + 95 = 334/650 = 0.51
Dataset 2:
Total number of plants = 368 + 112 + 125 + 38 = 643
Frequency of gene E = 368 + 112 = 480/643 = 0.75
Frequency of gene F = 368 + 125 = 493 / 643 = 0.77
Data set 3:
Total number of plants = 167 + 171 + 162 + 150 = 650
Frequency of gene E = 167 + 171 = 338 / 650 = 0.52
Frequency of gene F = 167 + 162 = 329 / 650 = 0.50
Data set 4:
Total number of plants = 301 + 287 + 25 + 37 = 650
Frequency of gene E = 301 + 287 = 588 / 650 = 0.90
Frequency of gene F = 301 + 25 = 326 / 650 = 0.50
Data set 5:
Total number of plants = 97 + 229 + 217 + 107 = 650
Frequency of gene E = 97 + 229 = 326 / 650 = 0.50
Frequency of gene F = 97 + 217 = 314 / 650 = 0.48
The data set 2,3 and 5 indicate that the genes E and F are linked.
