Two resistors In circuit 1 see the figure ohmic resistor R1

Two resistors In circuit 1 (see the figure), ohmic resistor R1 dissipates 2 watts; in circuit 2, ohmic resistor R2 dissipates 17 watts. The wires and batteries have negligible resistance. The circuits contain 10V batteries Circuit 1 Circuit 2 10 V 10 V R2 (a) What is the resistance of R1 and of R2? R1= R2= (b) Resistor R1 is made of a very thin metal wire that is 4 mm long, with a diameter of 0.1 mm. What is the electric field inside this metal resistor? V/m (c) The same resistors are used to construct circuit 3, using the same 10V battery as before Ri 10 V Circuit 3

Solution

a) R1=50 ohm, R2= 5.88 ohm

b) E = V/L2 = 10/ (4 x 10-3)
E = 2500 V/m

c) ? (no question)

d) current in circuit 3 = i = (10)/(50+5.88) = 0.179 A = (number od electrons)*charge of electron

so, n = 1.12*10^20

e) power output = (i^2)*R = (0.179)*(0.179)*(55.88) = 1.79 watt