For the circuit shown below Circuit Six determine the primar

For the circuit shown below (Circuit Six), determine the primary impedance (assume 0 Ohm winding resistance and an ideal transformer). We use the variable \"a\" as a = E_ primary/E_secondary = N_primary/N_secondary = N_primary: N_secondary Therefore, for this problem, a = 20-1 = 20 by simplifying the fraction. The textbook tells us that for an ideal transformer where we can ignore resistance and inductances within the transformer itself, we have for impedances: Z_primary = a^2 times Z_load If we assume we can use only resistance with no imaginary part at all, as we will for this problem, this simplifies to: R_primary = a^times R_Load

Solution

Rload=8 ohms.

from the given data

R primary=a^2*R load.

R primary=(20)^2*8=400*8=3200 ohms.

Z primary=R primary=3200 ohms.