xy9z32 xy2z4 x3y2z16Solutionxy9z32 xy2z4 x3y2z16 Subtracting

x+y+9z=32

x+y+2z=4

x-3y-2z=-16

Solution

x+y+9z=32

x+y+2z=4

x-3y-2z=-16

Subtracting first two equations ,we get

7z=28

z=4

substituting back the value of z in last two equations

x+ y= -4  

x-3y= -8

subtracting these two equations,we get

4y= 4

y=1

And x+y=-4

x+1=-4 x=-5