Consider a population that contains black and white cats whe
Solution
Answer:
1. False
Frequency of B = p2 + 1/2*2pq = 0.64 + 0.16 = 0.8
Frequency of b = q2 + 1/2*2pq = 0.04 + 0.16 = 0.2
So, p+q = 1, i.e, it follows HW equilibrium. So, the allele frequencies should remain constant.
2. True
Frequency of B = p2 + 1/2*2pq = 0.49 + 0.165 = 0.655
Frequency of b = q2 + 1/2*2pq = 0.16 + 0.165 = 0.325
So, p+q = 0.98, i.e, it doesnot follow HW equilibrium. So, evolutionary change is taking place.
3. True
Frequency of B = p2 + 1/2*2pq = 0.7 + 0.1 = 0.8
Frequency of b = q2 + 1/2*2pq = 0.1
So, p+q = 0.9, i.e, it doesnot follow HW equilibrium. So, evolutionary change is taking place.
4. True
Frequency of B = p2 + 1/2*2pq = 0.25 + 0.25 = 0.5
Frequency of b = q2 + 1/2*2pq = 0.25
So, p+q = 0.75, i.e, it doesnot follow HW equilibrium. So, evolutionary change is taking place.
