A car travels 330 miles in 6 hours It travels at 50 mph for

A car travels 330 miles in 6 hours. It travels at 50 mph for the first two hours and travels the last 180 miles at 60 miles per hour. It travels at constant speed for the remaining time.

Let x be the time traveled at the unknown constant speed.
The total itme for the trip was 6 hours so:
6 = time traveled at 50 mph + time traveled at 60 mph + time traveled at x mph.


(a) How long did it take to travel the first 150 miles? (hours)
(b) Where was the car after 3 hours? (miles from the start)

I thought the answer would be 100 (first two hours) plus 5/6 (50 min/60 min) since the second speed is traveling 60 miles, but we only want 50 of them, so the total would be 2+5/6 hours; but that wasn\'t right.
For the second part I thought it would be 100+60=160 for the first 2 hours (100 miles) + one more hour of 60mph, which would add 60. This wasn\'t right either.

Solution

A 100 B 50 C 180 D
Given, A car travels 330 miles in 6 hours.
total time = 330 miles.
total distance = 6 hours
It travels at 50 mph for the first two hours.
The ditanced in the first 2 hours = 2*50 = 100 miles.
It travels the last 180 miles at 60 miles per hour.
The time taken = 180/60 = 3 hours.
Distance travelled = 180 miles.
The balance time = 6-2-3 = 1 hour
The balance distance = 330-100-180 = 50 miles
It travels at constant speed for the remaining time.
a) Time taken by the car to travel the first 100 miles = 2 hours
Time taken by the car to travel the next 50 miles = 1 hours
So the time taken by the car to travel the first 150 miles = 2+1 = 3 hours
b) The car was at a distance of 150 miles from the starting point after 3 hours.