Does Technology Influence Gambling As a counselor in the fie
Does Technology Influence Gambling?
As a counselor in the field of addiction, you are interested in researching if online gambling is becoming more prevalent. You decide to conduct research to compare online gambling to gambling in public places such as casinos. You hypothesize that online gambling is more prevalent among those who are under the age 30, leading to more online gambling addictions in those individuals who are under 30. To test your hypothesis, you use a random sample of 40 individuals who report attending counseling because of a gambling addiction. The ages of the individuals and initial mode of gambling was recorded. The ages for those who gamble online and in public are shown in the table. On the basis of the data provided, can you conclude that online gambling is more prevalent among individuals who are under the age of 30 at a level of significance of 0.05? Why or why not? (Show all seven steps of the appropriate hypothesis test.)
PLEASE SHOW YOUR WORK
Online Gambling
Public Gambling
21
36
36
46
47
29
62
59
45
33
42
54
36
42
63
49
39
45
44
50
21
42
32
50
21
23
20
34
47
35
61
23
28
18
20
62
27
62
18
40
60
| Online Gambling | Public Gambling |
| 21 | 36 |
| 36 | 46 |
| 47 | 29 |
| 62 | 59 |
| 45 | 33 |
| 42 | 54 |
| 36 | 42 |
| 63 | 49 |
| 39 | 45 |
| 44 | 50 |
| 21 | 42 |
| 32 | 50 |
| 21 | 23 |
| 20 | 34 |
| 47 | 35 |
| 61 | 23 |
| 28 | |
| 18 | |
| 20 | |
| 62 | |
| 27 | |
| 62 | |
| 18 | |
| 40 | |
| 60 | |
Solution
Set Up Hypothesis
Null, online gambling is more prevalent among individuals, Ho: u1 > u2
Alternate, online gambling is less prevalent among individuals- H1: u1 < u2
Test Statistic
X(Mean)=38.88
Standard Deviation(s.d1)=16.066 ; Number(n1)=25
Y(Mean)=40.625
Standard Deviation(s.d2)=10.726; Number(n2)=16
we use Test Statistic (t) = (X-Y)/Sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =38.88-40.625/Sqrt((258.11636/25)+(115.04708/16))
to =-0.42
| to | =0.42
Critical Value
The Value of |t | with Min (n1-1, n2-1) i.e 15 d.f is 1.753
We got |to| = 0.41695 & | t | = 1.753
Make Decision
Hence Value of |to | < | t | and Here we Do not Reject Ho
P-Value:Left Tail - Ha : ( P < -0.417 ) = 0.34131
Hence Value of P0.05 < 0.34131,Here We Do not Reject Ho


