Use logs 2 04307 and log5 3 06826 to approximate the value o

Use logs 2 0.4307 and log_5 3 0.6826 to approximate the value of each expression.

Solution

log5(2) = 0.4307 ; log5(3) = 0.6826

12. log5(48) = log5(16*3) = log5(16) +log5(3)

= log5(2^4) +log5(3)

=4log5(2) +log5(3)

= 4*(0.4307) +0.6826 = 2.4054

13 log5(5/3) = log5(5) - log5(3)

= log5/log5 - log5(3)

= 1 - log5(3)

= 1-0.6826 = 0.3174