Value x of X PXx 4 029 3 021 0 2 4 014 Fill in the va

Value x of X

P=Xx

?4 = 0.29

?3 = 0.21

0 = ?

2   = ?

4 = 0.14

Fill in the values in the table below to give a legitimate probability distribution for the discrete random variable , whose possible values are , , , , and .

Solution

x P(X=x)

-4 0.29

-3 0.21

0 0.18

2 0.18

4 0.14