For a particular brand of batteries the distribution of the
Solution
We first get the z score for the critical value. As z = (x - u) / s, then as
x = critical value = 3
u = mean = 3.2
s = standard deviation = 0.5
Thus,
z = (x - u) / s = -0.4
Thus, using a table/technology, the right tailed area of this is
P(z > -0.4 ) = 0.655421742
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 10
p = the probability of a success = 0.655421742
x = the number of successes = 6
Thus, the probability is
P ( 6 ) = 0.23469068 [ANSWER]
