It is necessary to have a horizontal curve pass through a sp

It is necessary to have a horizontal curve pass through a specified point. The point was located by distance and angle from the PI of the curve (150 ft. and 32°00’00” to the left of the back tangent with the instrument located at the PI (see the illustration below).If the intersection angle is 50°00’00”, determine the curve radius required.

Solution

There is no illustration given which is discussed in question. But here the intersection angle is given as 50° which means the deflection angle will be 180°- 50° = 130°.

On assuming as the degree of as 3° curve, the radious of curve will be

R = 1720/D°

Which means R= 1720/3 =573.33 m.