Lightbulbs of a certain type are advertised as having an ave
Solution
Formulating the null and alternative hypotheses,
Ho: u >= 750
Ha: u < 750
As we can see, this is a left tailed test.
Thus, getting the critical z, as alpha = 0.05 ,
alpha = 0.05
zcrit = - 1.644853627
Getting the test statistic, as
X = sample mean = 738.44
uo = hypothesized mean = 750
n = sample size = 50
s = standard deviation = 38.2
Thus, z = (X - uo) * sqrt(n) / s = -2.139830992
Also, the p value is
p = 0.016184214
As z < 1.645, and P < 0.05, we REJECT THE NULL HYPOTHESIS.
Thus, there is significant evidence that the true average lifetime is smaller that what is advertised. [CONCLUSION]
