In an article appearing in TodaySolution So you are using sa

In an article appearing in Today

Solution

  So, you are using sample standard deviation which tells you to use the t distribution.

specifically, t = (x_bar - mu)/(s/sqrt(n))
t = 1.916
which is option \"B\"

you do have enough evidence to make a conclusion at the alpha = .05 level of signifcance, but we have to look that number up to actually make the conclusion. critical value is 2.093. So, you would conclude, do not reject Ho, and that the popcorn has the specified amount of calories (75).
I suppose to specifically answer this question - no the nutritionist does not have enough evidence to reject the claim, but is also unlikely to find that evidence.

In an article appearing in TodaySolution So, you are using sample standard deviation which tells you to use the t distribution. specifically, t = (x_bar - mu)/(

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