find all points on the x axis that are 14 units away from th

find all points on the x axis that are 14 units away from the point (5,-7)

Solution

Any point on x axis be ( x, 0)

This point is 14 units from ( 5, -7)

So, distance between ( x, 0) and ( 5, -7) = sqrt( ( 5-x)^2 +( -7)^2)

sqrt{ ( 5-x)^2 +49 } = 14 units

( 5-x)^2 +49 = 196

(5-x) = + /-sqrt(147)

x = 5 - sqrt(147) , 5 +sqrt(147)