Competition in the personal computer market is intense A sam
Competition in the personal computer market is intense. A sample of 450 purchases showed 202 Brand A computers, 175 Brand B computers, and 73 other computers. Use a .05 level of significance to test the null hypothesis that Brand A and Brand B have the same share of the personal computer market. What is p-value?
Solution
Formulating the hypotheses
Ho: pA^ - pB^ = 0
Ha: pA^ - pB^ =/= 0
Here, we see that pdo = 0 , the hypothesized population proportion difference.
Getting p1^ and p2^,
p1^ = x1/n1 = 0.448888889
p2 = x2/n2 = 0.388888889
Also, the standard error of the difference is
sd = sqrt[ p1 (1 - p1) / n1 + p2 (1 - p2) / n2] = 0.032830947
Thus,
z = [p1 - p2 - pdo]/sd = 1.827544015
As significance level = 0.05 , then the critical z is
zcrit = 1.959963985
Also, the p value is
P = 0.067618015 [ANSWER, P VALUE]
As p > 0.05, then we FAIL TO REJECT THE NULL HYPOTHESIS.
There is no significant evidence that Brand A and Brand B do NOT have the same share of the personal computer market. [conclusion]
