ASSEMBLY LANGUAGE Win32 Console Application solution in the

ASSEMBLY LANGUAGE (Win32 Console Application solution in the Microsoft Visual Studio)

Step for the solution: Count the number of odd values (n mod 2 <> 0) for each row. Note: Please use template the following template below as a base for the solution.

Important: All calculations, conditions and jumps must be implemented only with Inline or full assembler!

#include \"stdafx.h\"

#include

#include

void solution_for_grade_7(const int * arr, size_t arr_rows, size_t arr_cols, int * result)

{

    __asm

    {

        // Your Inline Assembler instructions for grade 7 level go here

        // :::

    }

}

const int ROWS = 2;

const int COLS = 3;

int main()

{

    // Change the array definitions to be appropriate for your assignments:

    int data1[ROWS][COLS] = { { 0, -1, 2 }, { 3, 4, -5 } };

    int result1[ROWS]; // Note: for some assignments the result size will depend on the COLS!

    // Change the parameters according to your assignment function, e.g.:

    solution_for_grade_7((const int *)data1, ROWS, COLS, result1);

    // Print the result one-dimensional array to the console:

    for (size_t i = 0; i < ROWS; i++)

        printf(\"%d \", res1[i]);

    // :::

    return 0;

}

Solution (Which I need but better also show me first step): Implement the same task \" Count the number of odd values (n mod 2 <> 0) for each row \" from previous step But place them in separate assembler module (in file with extension .ASM) and use the template below for assembler module. Important: Demonstrate assembler module by calling procedures from the C/C++ code.

.586

.model flat, C

.code

SolutionForGrade7 PROC PUBLIC USES ...

[LOCAL ...]

:::

ret

SolutionForGrade7 ENDP

:::

END

Solution

#include<stdio.h>
#include <iostream>
using namespace std;

int main(){

int nmbr;
int minn,maxx;
long cntt =0;

cout << \"Enter the minimum range: \";
cin >> minn;

cout << \"Enter the maximum range: \";
cin >> maxx;

for(nmbr = minn;nmbr <= maxx; nmbr++)
if(nmbr % 2 !=0)
cntt++;

cout << \"Number of odd numbers in given range is: \" << cntt;

return 0;

}