Evaluate the definite integral COS Solution put x2 6 t x3 d

Evaluate the definite integral.

COS

Solution

put x^2 /6 = t x/3 dx = dt xdx = 3dt so, substitute this cos(t) 3 dt 3 sint 3 sin(x^2/6) NOW APPLY THE LIMITS 3 sin(3pi/2) - 0 3 (-1) -3 ANSWER