state the coordinates of the vertex for the given parabola y
state the coordinates of the vertex for the given parabola: y^2+4y-10+2x=0 Please show your steps.
Solution
y^2+4y-10+2x=0
standard equation of parabola in vertex form is
(y-k)^2 = a (x - h)
y^2+4y = -2x + 10
( y + 2)^2 - 4 = -2x+10 +4
adding 4 on both sides
(y+2)^2 = -2x + 14
(y+2)^2 = -2(x-7)
therefore, vertex is ( 7,-2)
