In an experiment to compare the tensile strengths of I 5 di

In an experiment to compare the tensile strengths of I = 5 different types of copper wire, J = 4 samples of each type were used. The between-samples and within-samples estimates of sigma^2 were computed as MSTr = 2690.3 and MSE = 1106.2, respectively. Use the F test at level 0.05 to test H_0: mu_1 = mu_2 = =mu_5 versus H_a: at least two mu j s are unequal. Calculate the test statistic. f =

Solution

   Mean Square Between = SS Between / df Between = 2690.3  
   Mean Square Within = SS Within / df Within = 1106.20
                                                                      
   F Cal = MS Between / Ms Within = 2690.3/1106.20 = 2.43201 ~ 2.43