Homework SourseOnly 17 of the work population used Internet in 1997 wherea
Only 1.7 % of the work population used Internet in 1997 whereas 28.8% of the world Population used in 2010.assuming continuous exponential growth find the year in which the precentage will reach %100
Ani paid $ 12075 for Toyota. after 3 years it was 11981 .assume that the price is decreasing according to continuous exponential decay model p=p0ert
A )find th annual depreciation rate to the nearest tenth of a percent
B) find the value of the car after 5 years to the nearest hundred dollar
Only 1.7 % of the work population used Internet in 1997 whereas 28.8% of the world Population used in 2010.assuming continuous exponential growth find the year in which the precentage will reach %100
Ani paid $ 12075 for Toyota. after 3 years it was 11981 .assume that the price is decreasing according to continuous exponential decay model p=p0ert
A )find th annual depreciation rate to the nearest tenth of a percent
B) find the value of the car after 5 years to the nearest hundred dollar
Ani paid $ 12075 for Toyota. after 3 years it was 11981 .assume that the price is decreasing according to continuous exponential decay model p=p0ert
A )find th annual depreciation rate to the nearest tenth of a percent
B) find the value of the car after 5 years to the nearest hundred dollar
Solution
Assuming 1997 as the starting year, Po = 1.7%
Now after 13 years, P = 28.8%
P = Po*e^(rt)
28.8 = 1.7 * e^(r*(2010-1997)
16.94 = e^(r*13)
taking ln both sides we get
ln(16.94) = 13*r
r = ln(16.94)/13 = 0.217
Hence model is P = 1.7*e^(0.217*t)
When it will be 100% ?
100 = 1.7 * e^(0.217*t)
ln(58.82) = 0.217*t
t = 18.77
Hence it will be 100% by 1997 + 19 = 2016
b)
Amount Paid = $12,075
After 3 years, $11981
P = Po * e^(-rt)
11981 = 12075 * e^(-r*3)
0.9922 = e^(-3r)
take ln both sides we get
ln(0.9922) = -3r
r = 0.002615
After 5 years, it will be
P = Po * e^(-rt) = 12075 * e^(-0.002615*5) = 11918.43$
