Answer the question and fill in the blank line below This is

Answer the question and fill in the blank line below( This is assembly language question):

What does the programmer what to find out from the following algorithm:   

IF 2*(X÷2) = X THEN

BEGIN

EVEN := 1                            

END

IF 2*(X÷2) <> X THEN

BEGIN

ODD:= 1

END

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Solution

The programmer want to find out, if X is even or not.

2*(X÷2) = X      will be true only if X is an even number else X is odd number, same is being done in the given code. Note that, first division operator is executed and then multiplication by 2.

For example if X= 12,     X÷2 = 6 ,   2*(X÷2) = 12 = X

                     if X = 15,    X÷2 = 7    Note that X is integer, dividing by 2 is also stored as integer

                                        2*(X÷2) = 14 <> X