3 Find the currents in the figure below if R10 and AV10 volt

3. Find the currents in the figure below if R-1.0 and AV-10 volts. 2.4 : 9.0

R and 9 ohms are in parallel

1/R₁ =1/9 + 1/1

R₁=0.9 ohms

0.9 and 2.4 ohms are in series

R₂=0.9+2.4 =3.3 ohms

3.3 and R=1 ohms are in parallel

1/R₃ = 1/1+1/3.3

R₃=0.76744 ohms

R,R and R₃ are in series ,so equivalent resistance is

R_eq=1+1+0.76744 =2.76744 ohms

So Total Current flowing in the circuit is

I=V/R_eq=10/2.76744

I=3.6 A

SO current through each resistor is

I₁=I=3.6 A

By Current divider rule

I₂=I₁*(R₂/R+R₂)=3.6*(3.3/3.3+1)

I₂=2.77 A

I₃=I₁-I₂ =3.6-2.77 =0.83 A

I₄=I₃*(9/9+1) =0.83*0.9 =0.747 A

I₅=0.83-0.747 =0.083 A