only looking for help with questions 8 and 9 Sample Group Da
only looking for help with questions 8 and 9
Solution
mean :
(36 + 48 + 54 + 42 + 60 + 36) / 6
mean = 46
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median :
Arrange in ascending order first
36 , 36 , 42 , 48 , 54 , 60
We have 6 terms
so the two middle termsare the 3rd and 4th terms
42 and 48
So, median = avg of 42 and 48
(42 + 48) / 2
45
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mode :
36 occurs most frequently
So, mode = 36
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Range :
Largest - Least
60 - 36
24
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9)
Standard deviation :
Comes out to
10
