Use the given information to find the values of the remainin

Use the given information to find the values of the remaining five trigonometric functions. (Enter your answers in exact form.)

tan x = 8, pie/2 <x < pie

tanx=-8

x lies in second quadrant

here opposite=8 and adjacent =1

Therefore hypotenuse=sqrt(8^2 + 1^2)=sqrt65

And in second quadrant sine and csc are positive and all others are negative

sin theta=opposite/hypotenuse

sinx=8/sqrt65=8sqrt65/65

csc theta=1/sin theta

csc x= sqrt65/8

cos theta=adjacent/hypotenuse

cos x=-1/sqrt65=-sqrt65/65

sec theta=1/cos theta

sec x=1/cos x=-sqrt 65

cot theta= 1/tan theta

cot x= -1/8