I couldnt understand how to solve this could anyone help me
Solution
let number of one-bedroom units be x
let number of two-bedroom units be y
and let number of three-bedroom units be z
Given that total number of units planned are 216
==> x + y + z = 216 --------- (1)
Also given that number of family units (one and two bedroom units) will equal the number of one bedroom units
==> y + z = x -------- (2)
And number of one - bedroom units are three times the number of three - bedroom units
==> x = 3z ----- (3)
from (1) and (2)
Substitute (2) in (1)
==> x + (x) = 216
==> 2x = 216
==> x = 108
substitute x = 108 in (3)
==> 108 = 3z
==> z = 108/3
==> z = 36
Substitute z = 36 and x = 108 in (2)
y + 36 = 108
==> y = 108 - 36
==> y = 72
Hence number of one-bedroom units are x = 108
number of two-bedroom units are y = 72
number of three-bedroom units are z = 36
