The following function openFile attempts to open a file that

The following function openFile() attempts to open a file that does not exist, and raises a FileNotFoundError exception.

def openFile():

\'open hambone.txt and read content\'

infile = open( \'hambone.txt\', \'r\' )

content = infile.read()

infile.close()

Write a function tryOpenFile()that takes no input arguments. The function should wrap the function call to openFile() in try/except statements to handle the error, so that the program does not enter an erroneous state. When called, the function will print out the following message: \"hambone.txt file could not be found\"

This means you will need to include the function definition for openFile() in your module.

Test calling tryOpenFile() function in the interactive shell.

Solution

def openFile():
   \'open hambone.txt and read content\'
   infile = open( \'hambone.txt\', \'r\' )
   content = infile.read()
   infile.close()
def tryOpenFile():
   try:
       openFile()
   except:
       print \"hambone.txt file could not be found.\"
tryOpenFile()

# sample output

# hambone.txt file could not be found