suppose that w u2v where u g1t and v g2t are differentiab
suppose that w = u^2/v where u = g1(t) and v = g2(t) are differentiable functions of t. If g1(1)= 3 g2(1) = 2 the first derivative of g(1) = 5 and the first derivative of g(2) = -4 find dw/dt when t = 1
Solution
g1(1) = 3 g2(1) = 2 g1\'(1) = 5 g2\'(1) = -4 w\' = { v(2uu\') - u^2(v\') } / v^2 at t=1 w\' = { 2(2*3*5) - 3^2(-4) } / 2^2 = 24