Given that PA 314 PB 16 PC 13 PA and C 17 and PB l C 52

Given that P(A) = 3/14, P(B) = 1/6, P(C) = 1/3, P(A and C) = 1/7, and P(B l C) = 5/21, find the following probabilities:

a) P(A l C)

b) P(C l A)

c) P(B and C)

d)P(C l B

A)P(A l C) = P(A AND C)/P(C) = (1/7)/(1/3)= 3/7

B)P(C l A) = P(A AND C)/P(A) = (1/7)/(3/14) = 2/3

C) P(B and C) = P(B l C)* P(C) = 5/21*1/3 = 5/63

D)P(C l B) = P( C AND B)/P(B) = (5/63)/(1/6)= 30/63