An insurance company offers four different deductible levels

An insurance company offers four different deductible levels-none, low, medium, and high-for its homeowner\'s policyholders and three different levels-low, medium, and high-for its automobile policyholders. The accompanying table gives proportions for the various categories of policyholders who have both types of insurance. For example, the proportion of individuals with both low homeowner\'s deductible and low auto deductible is 0.05 (5% of all such individuals). Suppose an individual having both types of policies is randomly selected. (a) What is the probability that the individual has a medium auto deductible and a high homeowner\'s deductible? (b) What is the probability that the individual has a low auto deductible? A low homeowner\'s deductible? auto deductible Homeowner\'s deductible (c) What is the probability that the individual is in the same category for both auto and homeowner\'s deductibles? (d) Based on your answer in part (c), what is the probability that the two categories are different? (e) What is the probability that the individual has at least one low deductible level? (f) Using the answer in part (e), what is the probability that neither deductible level is low?

Solution

A) “And” corresponds to the intersection of the high home column and the medium auto row, which is 0.10. B)Summing the entire row for low auto: 0.04+0.06+0.05+0.03 = .18 Summing the entire column for low home: 0.06 + 0.10 + 0.03 = .19 C )Sum the diagonal where both home and auto policies are low, medium, and high: 0.06 + 0.20 + 0.15 = .41 D) This is the compliment of the event defined in (c): 1-.41 = .59 E)Sum both the low auto row and low home column but don’t double count the intersection: (0.04+0.06+0.05+0.03) + (0.06+.10+.03) – 0.06 = .31 F)Again, taking the compliment of (e): 1-.31 = .69