a Show the inferred chromosomal constitutions of the parents
Solution
1. Map units are measure of tendency of cross over to occur between two loci.
2. If genes are farther apart will have higher likelihood of crossover, the higher the crossover frequency.
3. The test cross data allows indirectly to measure the frequency of gamates made by an individual.
4. All of the test cross progeny inherited a gamete with recessive \'a\' and \'b\' colourless shrunken parent.
5. So the alleles of the F1 dihybrid parent have passed on trait in the seed.
Parents Colored shrunken (AAbb) X Colorless full (aaBB)
Gamets Ab aB
F1 generation Colored full (AaBb)
If F1 crossed with Colorless shrunken(tester strian), F2 generation we got the above data.
In the above data Colored full : 920
Colored shrunken : 15,800
Colorless full : 16,000
Colorless shrunken : 900 Total are: 33,620
Colored full and colorless shrunken are parental type, Colored shrunken and Colorless full are recombinant type.
Recombination frequency= recombinant types/Total no. of progeny*100
Recombinant types are colored full 920+ colorless shrunken 900 = 1820
Recombination frequency= 1820/33620 = 0.0541X100 = 5.41mu.
